Skip to main content

Amount of substance calculation

Chemists use amount of substance for counting atoms. This uses moles to find out said substance by using relative atomic mass and the weight of the substance. This is represented by:

n=m/M                      n=Moles
                                  m=Mass
                                  M= Molar mass (relative atomic mass)

To find out molar mass of a substance you can look at a periodic table and looking at the mass number (larger number above the element) for example carbons mass number is 12 NOT 6 as this is atomic mass.

A simple example of this would be using carbon. First try this on your own using the formula above, if you have trouble follow this through after writing the question down.

How many moles are there in 48g of carbon?

Now let run through this piece by piece and we will break it down and increase difficulty as we run through different examples.

Returning to the original formula which is:

n=m/M

Looking at the periodic table of elements we can see that Carbon has a molar mass of 12 due to the mass of the element being 12. Now aware of this we can put both the molar mass and the amount of substance into this:

n=48/12

At this point you can most likely calculate this in your head and come up with 3 but in harder calculations feel free to use your calculator as it is allowed during tests! So now you can do simple calculations with singular elements, let try it with a substance now...

How many moles are there in 11g of carbon dioxide?

Keeping in mind balancing of equations which are pretty simple (If you are struggling check out my balancing equations post) we should know that carbon dioxide in symbol form is CO2. Being that we are now working with a substance we need to find out the molar mass of the whole substance.

Carbon as before is still 12 but now we have two lots of Oxygen which equals 32 (16 on its own) and to find the molar mass of the entire substance we add it all together resulting in  a Mr of 44. Now it's just a matter of plugging what you have into the same equation:

n=m/M
n=11/48=0.250 mol

Alternatively, you may be given a similar question but asked in a different format, to solve this you just alter the equation to suit the needs of your new question. For example:

Calculate the mass in grams in 3 moles of SiO2

Once again we find the molar mass by adding the mass of the different elements.

Si=28
O2=32

SiO2=60

Now we just need to rearrange the formula to fit to the data you have in which case we have th molar mass and the moles. The new equation would be:

m=n x M
m=60 x 3= 180g

This is all you need to know about the amount of substance formula!

Till Next tyme! :)


Comments

Popular posts from this blog

Electrons and orbitals

So everything you were taught at GCSE by your teachers, yeah that was all a lie, completely forget that they lied to you! Electron shells aren't flat they are 3D and that issue with going past 20 electrons? Fret no more because we can now get past this, admittedly with a lot of work but what doesn't kill you makes you stronger! So these electron orbitals are filled with sub levels, remember the 2.8.8.2 formula? Well it turns out they were actually sub levels in an atom, here take a look: As you can see the shells are known as 'n' and the number of that orbital increases the further away it gets. Now not to confuse you but technically they are all on top of each other and the distance between each of these is miniscule! When drawing them though I recommended giving them space otherwise you are not going to be working with a lot! So lets take a deep look at this: Orbitals are known as S, P, D, F and so on but you don't really need to know any further for now. No...

Titration Calculation

 So... next set of never ending calculations is.... the titration calculation. Fun times right? Lets get this on the road! What is a titration? Simply put it is the neutralization of an acid by an alkali or vice versa to an immensely accurate scale - not flawless though mind, just saying (problematic I know but it is 2020!).  Be careful when measuring values in the burette, it needs to be read from the meniscus - this is the dip of the solution in the burette. Also just to annoy you that little bit more, you have to record and record and record and record and record and record and record.... oh sorry lost myself there! (it is true though!) ... until you get two results that are concordant with one another (within 0.1 of each other). So lets get down to the ever so enjoyable maths... Ca(OH)₂ + HNO₃ ---> Ca(NO₃)₂ + H₂O So here we have our lovely little equation. Now I recommend simply balancing this out - having issues? check this out - as balancin...

Redox Reactions

OIL RIG These two words you are undoubtable familiar with since GCSE chemistry - or at least I would hope so! OIL RIG refers to oxidation and reduction, you may ask: what are these two terms? Well the definitions are simple: Oxidation refers to the loss of electrons or the gaining of oxygen. Reduction is the polar opposite as it refers to the gain of electrons and the loss of oxygen. Oxidation and reduction are like two of your friends who really like each other and they never stop being together (weird analogy I know) as they always go hand in hand, somewhat of a package deal: you buy one, you get one free! When there is a reaction where reduction takes place, oxidation won't be far behind and vice versa, this is because when reduction occurs oxidation must take place also. It like that cringe quote: 'every action has an equal and opposite reaction.' which makes sense because they do the opposite of each other. When reduction and oxidation occurs in a reaction the...